Answer:
Deceleration of the runner is -23.33 [tex]\frac{m}{s^{2} }[/tex]
Given:
Initial velocity = 3.5 [tex]\frac{m}{s}[/tex]
Final velocity = 0 [tex]\frac{m}{s}[/tex]
Time = 0.15 s
To find:
Deceleration of runner = ?
Formula used:
According to first equation of motion,
v = u + at
Where, v = final velocity
u = initial velocity
a = deceleration
t = time
Solution:
According to first equation of motion,
v = u + at
Where, v = final velocity
u = initial velocity
a = deceleration
t = time
0 = 3.5 + a (0.15)
-3.5 = 0.15 (a)
a = [tex]\frac{-3.5}{0.15}[/tex]
a = -23.33 [tex]\frac{m}{s^{2} }[/tex]
Negative sign shows that it is deceleration.
Thus, deceleration of the runner is -23.33 [tex]\frac{m}{s^{2} }[/tex]
