Question

Which of the following is a valid mole ratio from the balanced equation 2C3H6 + 9O2 → 6CO2 + 6H2O?
1 mole of C3 H6/ 2 moles of C O2
6 moles of H2 O/ 9 moles of O2
2moles of C3 H6/ 6 moles of O2
3 moles of H2 O/ 2 moles of C O2

Answer 1

Answer:

                  6 moles of H₂O / 9 moles of O₂

Explanation:

The Balance Chemical Equation is as follow,

                                    2 C₃H₆ +  9 O₂     →   6 CO₂  + 6 H₂O

According to this balance equation 2 moles of C₃H₆ (Propene) when combusted with 9 moles of O₂ (Oxygen) produces 6 moles of CO₂ (Carbon Dioxide) and 6 moles of H₂O (Water Vapors).

Hence, Given options are;

1 mole of C₃H₆ / 2 moles of CO₂: This is incorrect because 1 mole of C₃H₆ will produce 2 moles of CO₂.

6 moles of H₂O / 9 moles of O₂: This is correct as 6 moles of H₂O is produced by reacting 9 moles of O₂.

2 moles of C₃H₆ / 6 moles of O₂: This ratio is incorrect because for complete oxidation 2 moles of C₃H₆ requires 9 moles of O₂.

3 moles of H₂O / 2 moles of CO₂: This is also incorrect because the production of 3 moles of H₂O will be accompanied by the production of 3 moles of CO₂.

Answer 2

The valid mole ratio from the balanced equation of 2C3H6 + 9O2 → 6CO2 + 6H2O is seen in the second option. 6 moles of H2 O/ 9 moles of O2

A balanced chemical equation usually comprises equal moles of chemical compounds or elements on both the reactant side and the product side.

From the given chemical equation;

Two moles of C3H6(ethene) react with nine moles of oxygen (O2) to produce six moles of CO2 (carbon dioxide) and six moles of water (H2O).

From the given information, the claim that:

• 1 mole of C3 H6 results into 2 moles of C O2 is incorrect.
• 6 moles of H2 O results into 9 moles of O2 is correct.
• 2 moles of C3H6 results into 6 moles of O2 is incorrect.
• 3 moles of H2O results into 2 moles of CO2 is incorrect.

Learn more about balanced chemical equations here:

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