Question

A metal rod is 25.000 cm long at 25.0 degrees Celsius. When heated to 102.0 degrees Celsius, it is 25.054 cm long. What is the coefficient of linear expansion for this metal?

Answer 1

We need to find coefficient of linear expansion for the metal

Change in temperature = 102 -25 = 77 degree Celsius

Change in length = 25.054 - 25.000 = 0.054 cm

Expansion because of rise in temperature = lαΔT

                                         0.054 = 25.000*α*77

                                              α = $2.8*10^{-5}$ $^0C^{-1}$

So coefficient of linear expansion for the metal = $2.8*10^{-5}$ $^0C^{-1}$

Answer 2

The coefficient of linear expansion of the metal is 2.8×10¯⁵ K¯¹

From the question given above, the following data were obtained:

Original length (L₁) = 25 cm

Initial temperature (T₁) = 25 °C

Final temperature (T₂) = 102 °C

Final length (L₂) = 25.054 cm

Coefficient of linear expansion (α) =?

The coefficient of linear expansion of the metal can be obtained as follow:

$\alpha = \frac{L_{2} - L_{1}}{L_{1}(T_{2} - T_{1})}\\\\\alpha = \frac{25.054 - 25}{25(102 - 25)}$

α = 2.8×10¯⁵ K¯¹

Therefore, the coefficient of linear expansion of the metal is 2.8×10¯⁵ K¯¹

Learn more: https://brainly.com/question/14373396