Answer:- molecular formula is [tex]PdC_4H_6O_4[/tex] .
Solution:- Percentages are given from which we will calculate the moles of each element.
moles of Pd = [tex]47.40gPd(\frac{1mol}{106.42g})[/tex] = 0.445 mol Pd
moles of O = [tex]28.50gO(\frac{1mol}{16g})[/tex] = 1.78 mol O
moles of C = [tex]21.40gC(\frac{1mol}{12.01g})[/tex] = 1.78 mol C
moles of H = [tex]2.69gH(\frac{1mol}{1.01g})[/tex] = 2.66 mol H
Now we divide the moles of each by the least one of them. The least one is 0.445. So, let's divide the moles of each by 0.445.
Pd = [tex]\frac{0.445}{0.445}[/tex] = 1
O = [tex]\frac{1.78}{0.445}[/tex] = 4
C = [tex]\frac{1.78}{0.445}[/tex] = 4
H = [tex]\frac{2.66}{0.445}[/tex] = 6
So, the molecular formula of the compound is [tex]PdC_4H_6O_4[/tex] .
