we know that
The difference of squares is two terms that are squared and separated by a subtraction sign
so
[tex]a^{2}-b^{2}=(a+b)*(a-b)[/tex]
Part a)
we have
[tex]x^{2}-30[/tex]
we know that
[tex]\sqrt{30}[/tex] -------> is not a integer
so
The number 30 is not a perfect square number
therefore
the answer part a) is the option
4. No because the 30 is not a perfect square number
Part b)
we have
[tex](16x^{2}-25)[/tex]
we know that
[tex]16x^{2}=(4x)^{2} \\25=5^{2}[/tex]
so
[tex](16x^{2}-25)=(4x)^{2}-5^{2}=(4x+5)*(4x-5)[/tex]
therefore
the answer part b) is the option
2. (4x−5)(4x+5)