Question

A fly undergoes a displacement of -5.80 m while accelerating at -1.33m/s^2 for 4.22 s what was the initial velocity of the fly?

Answer 1

The fly's average velocity over the 4.22 second interval is

$\bar v=\dfrac{-5.80\,\mathrm m}{4.22\,\mathrm s}=-1.37\,\dfrac{\mathrm m}{\mathrm s}$

If the fly's acceleration is uniform over the interval, then we also have

$\bar v=\dfrac{v_i+v_f}2\implies v_i+v_f=-2.74\,\dfrac{\mathrm m}{\mathrm s}$

With the given acceleration we can get another relation involving the initial and final velocities:

$-1.33\,\dfrac{\mathrm m}{\mathrm s^2}=\dfrac{v_f-v_i}{4.22\,\mathrm s}\implies -v_i+v_f=-5.61\,\dfrac{\mathrm m}{\mathrm s}$

Solving this system, in particular for $v_i$, we find

$v_i=1.44\,\dfrac{\mathrm m}{\mathrm s}$

Answer 2

The initial velocity of the fly is  1.44 m/s.

What is acceleration?

Acceleration is given by the ratio of resultant or total force acting on any object and the its mass.

It can also be defined as the rate change of velocity with time.

acceleration a = (Δv) / (Δt)

The average velocity of fly over the 4.22 second interval is

v = -5.80 /4.22 = -1.37 m/s

If the average velocity can be written as

v = vi +vf /2

vi +vf = -2.74 m/s...................(1)

from the definition of acceleration,  we have

-1.33 =vf -vi /4.22

vf -vi = -5.61 m/s....................(2)

Solving both the equations, we get the initial velocity as

vi = 1.44 m/s

Learn more about acceleration.

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