The correct answer is (2) Freezing
The “latent heat of fusion” for water is the amount of energy we need to add to 0ºC ice to turn it into 0ºC water. Its symbol is
∆Hfusion or ∆Hfus.
For water, ∆Hfus = 334 J/g = 80 calories/gram
That means it takes 334 joules of energy to turn each gram of 0ºC ice into 0ºC water.
SO we can say that 334 joules of energy are released when each gram of 0ºC water freezes and becomes 0ºC ice.