Respuesta :
Answer:
Time required by boat 1 for the round trip is less than that of boat 2.
Hence, boat 1 wins.
Explanation:
Case 1: Boat 1
Speed of boat = [tex]\frac{distance of river}{time}[/tex]
time = [tex]\frac{distance of river}{speed of boat}[/tex]
While going to another end
time = [tex]\frac{distance of river}{speed of boat}[/tex]
time = [tex]\frac{48}{48}[/tex]
time = 1 hour
While going back,
time = [tex]\frac{distance of river}{speed of boat}[/tex]
time = [tex]\frac{48}{48}[/tex]
time = 1 hour
Total time taken by boat 1 is,
Total time by boat 1 = 1 hour + 1 hour = 2 hour
Total time by boat 1 = 2 hour
Total time taken by boat 1 for the round trip is 2 hour.
Case 2: Boat 2
Speed of boat = [tex]\frac{distance of river}{time}[/tex]
time = [tex]\frac{distance of river}{speed of boat}[/tex]
While going to another end
time = [tex]\frac{distance of river}{speed of boat}[/tex]
time = [tex]\frac{48}{24}[/tex]
time = 2 hour
While going back,
time = [tex]\frac{distance of river}{speed of boat}[/tex]
time = [tex]\frac{48}{72}[/tex]
time = 0.66 hour
Total time taken by boat 2 is,
Total time by boat 1 = 2 hour + 0.66 hour
Total time by boat 1 = 2.66 hour
Total time taken by boat 2 for the round trip is 2.66 hour.
Time required by boat 1 for the round trip is less than that of boat 2.
Hence, boat 1 wins.