Two boats start together and race across a 48-km-wide lake and back. boat a goes across at 48 km/h and returns at 48 km/h. boat b goes across at 24 km/h, and its crew, realizing how far behind it is getting, returns at 72 km/h. turnaround times are negligible, and the boat that completes the round trip first wins. (a) which boat wins? (or is it a tie?)

Respuesta :

Answer:

Time required by boat 1 for the round trip is less than that of boat 2.

Hence, boat 1 wins.

Explanation:

Case 1: Boat 1

Speed of boat = [tex]\frac{distance of river}{time}[/tex]

time = [tex]\frac{distance of river}{speed of boat}[/tex]

While going to another end

time = [tex]\frac{distance of river}{speed of boat}[/tex]

time = [tex]\frac{48}{48}[/tex]

time = 1 hour

While going back,

time = [tex]\frac{distance of river}{speed of boat}[/tex]

time = [tex]\frac{48}{48}[/tex]

time = 1 hour

Total time taken by boat 1 is,

Total time by boat 1 = 1 hour + 1 hour = 2 hour

Total time by boat 1 = 2 hour

Total time taken by boat 1 for the round trip is 2 hour.

Case 2: Boat 2

Speed of boat = [tex]\frac{distance of river}{time}[/tex]

time = [tex]\frac{distance of river}{speed of boat}[/tex]

While going to another end

time = [tex]\frac{distance of river}{speed of boat}[/tex]

time = [tex]\frac{48}{24}[/tex]

time = 2 hour

While going back,

time = [tex]\frac{distance of river}{speed of boat}[/tex]

time = [tex]\frac{48}{72}[/tex]

time = 0.66 hour

Total time taken by boat 2 is,

Total time by boat 1 = 2 hour + 0.66 hour

Total time by boat 1 = 2.66 hour

Total time taken by boat 2 for the round trip is 2.66 hour.

Time required by boat 1 for the round trip is less than that of boat 2.

Hence, boat 1 wins.