Question

Given that you added 5 ug of a purified acid phosphatase to tube a, calculate the amount of acid phosphatase (in ug) that was present in the 400ul of the wheat germ extract in tube b

Answer 1

solution:

$Amount of purified acid phosphatase added to tube A = 5\mu g(micrograms)\\

Amount of acid phosphatase present in 400\mu g of wheat germ extract in tube B=1/100=5x/400\\

100x=(0.5)(400)\\

X=(0.5)(400)/100=2\mu g\\

The amount of acid phosphatase present in 400\mu g of the wheat germ extract in tube B is 2\mu g$