Question

The gas in an engine cylinder is compressed until it has a volume of 0.045 liter and an absolute pressure of 28 atmospheres. If the engine cylinder contains 0.020 mole of gas, what is its temperature? The temperature of the gas is how many K.

Answer 1

The  temperature  in K  is  767.4 K

 calculation

This is calculated using the ideal gas equation

that is PV =nRT

where;

P(pressure)= 28 atm

V(volume) = 0.045 L

n(number of moles)= 0.020 moles

R( gas  constant)  =0.0821 L.atm/mol.K

T(temperature)= ? K\

make T the subject of   the formula  by diving  both side of equation by nR

T =PV/nR

T ={ (28 atm x 0.045 L) /( 0.020 mol x 0.0821 L.atm/mol.K)}  =767.4 K

Answer 2

Answer:

The answer is 770 K.

Explanation:

You have to round the answer to two significant figures to get the answer correct for Edmentum.