Q2: angle 3 = 82 . angle 4 = 56 . angle 5 = 42 . angle 6 = 82 . angle 7 = 98 . angle 8 = 82. angle 9 = 98 . angle 10 = 82 . angle 11 = 40 . angle 12 = 140 . angle 13 = 40 . angle 14 = 190
they are some V.O.As and triangles and alternative angles and angles on same straight line.
Q3: Since CD bisects < ABC (given)
therefore m(<CDA) = m(<CDB) = 90. (1)
Therefore m(<ACD) = m(<BCD). (2)
Since CD is a mutual side between Triangle CDA and Triangle CDB. (3)
From (1),(2) and (3)
Therefore triangle CDA is congrant to triangle CDB
