Question

a student is pushing a 50kg cart, with a force of 600N. another student measures the speed of the cart, and finds that the cart is only accelerating at 3/m2. how much friction must be acting on the cart.(hint draw a diagram showing the cart, and the two forces acting on it.

Answer 1

Answer:

frictional force acting on the cart 450 N.

Given:

mass of cart = 50 kg

acceleration = 3 $\frac{m}{s^{2} }$

To find:

Frictional force = ?

Formula used:

F - $F_{k}$ = 600 N

F = ma

$F_{k}$ = frictional force

Solution:

Force on the block is given by,

F - $F_{k}$ = 600 N

F = ma

$F_{k}$ = frictional force

$F_{k}$ = 600 - m a

$F_{k}$ = 600 - (50 × 3)

$F_{k}$ = 600- 150

$F_{k}$ = 450 N

According to the given data the frictional force acting on the cart 450 N.

Answer 2

The amount of friction which must be acting on the cart is 450 Newton.

Given the following data:

• Mass of cart = 50 kg

• Force = 600 Newton

• Acceleration = 3 $m/s^2$

To find how much friction must be acting on the cart, we would Newton's Second Law of Motion:

$Net\; force = Force + Frictional\; force$    ....equation 1.

Rearranging the eqn, we have:

$Frictional\; force = Force - Net\; force$    ....equation 2.

To solve for the net force:

$Net \;force = mass \times acceleration\\\\Net \;force = 50 \times 3$

Net force = 150 Newton

Substituting the values into eqn 2, we have:

$Frictional\; force = 600 - 150$

Frictional force = 450 Newton

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