Question

What is the mass in grams of 0.699 mol of glucose, c6h12o6?

Answer 1

The mass of 0.699 mol of C₆H₁₂O₆ is 126 g.

Mass = 0.699 mol × (180.16 g/1 mol) = 126 g

Answer 2

Answer:

$m_{gluc}=125.82g$

Explanation:

Hi, first you need to calculate the molecular weight of the glucose:

Knowing that the atomic weights are:

C=12

H=1

O=16

$Mr_{gluc}=6*12+12+6*16$

$Mr_{gluc}=180$

By definition the Mr is the weight in grams of 1 mol of the sustance. So:

$m_{gluc}=\frac{180g}{mol}*0.699mol$

$m_{gluc}=125.82g$