1212 times a number xxx, subtracted from 343434, is greater than 8.8.8, point Write an inequality for the statement above. Find the solution set of the inequality. Write the solution using a fraction or integer.

Respuesta :

The variable is taken x for unknown number here.

Given statement: 12 times a number x subtracted from 34 is greater than 8.

Times represents multiplication operation.

12 times x = 12*x = 12x.

So, we setup an inequality for above statement as

34 -12x > 8.

Therefore, required inequality is 34 -12x > 8.

Let us solve the inequality for x now.

34 -12x >8

Subtracting 34 from both sides, we get

34-34 -12x > 8-34

-12x > -26.

Dividing both sides by -12, we get

-12x/-12 > -26/-12

x < 13/6. ( Note: on dividing by a negative number, the inequality sign get flip).

So, the solution is x< 13/6.


Answer:

[tex]x<\frac{13}{6}[/tex] and [tex](-\infty,\frac{13}{6})[/tex].

Step-by-step explanation:

We have been given that 12 times a number x is subtracted from 34, is greater than 0.8.

Let use translate our given statement in an inequality.

12 times a number x would be [tex]12x[/tex].

We have been given that 12 times a number x is subtracted from 34, so our expression would be: [tex]34-12x[/tex].

12 times a number x is subtracted from 34, is greater than 0.8.  We can represent this information in an inequality as:

[tex]34-12x>8[/tex]

Let us solve for x.

[tex]34-34-12x>8-34[/tex]

[tex]-12x>-26[/tex]

We know that dividing inequality by a negative number flips inequality sign.

[tex]\frac{-12x}{-12}<\frac{-26}{-12}[/tex]

[tex]x<\frac{13}{6}[/tex]

Therefore, the solution for our given inequality is [tex]x<\frac{13}{6}[/tex] and [tex](-\infty,\frac{13}{6})[/tex] interval notation.

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