Respuesta :
The variable is taken x for unknown number here.
Given statement: 12 times a number x subtracted from 34 is greater than 8.
Times represents multiplication operation.
12 times x = 12*x = 12x.
So, we setup an inequality for above statement as
34 -12x > 8.
Therefore, required inequality is 34 -12x > 8.
Let us solve the inequality for x now.
34 -12x >8
Subtracting 34 from both sides, we get
34-34 -12x > 8-34
-12x > -26.
Dividing both sides by -12, we get
-12x/-12 > -26/-12
x < 13/6. ( Note: on dividing by a negative number, the inequality sign get flip).
So, the solution is x< 13/6.
Answer:
[tex]x<\frac{13}{6}[/tex] and [tex](-\infty,\frac{13}{6})[/tex].
Step-by-step explanation:
We have been given that 12 times a number x is subtracted from 34, is greater than 0.8.
Let use translate our given statement in an inequality.
12 times a number x would be [tex]12x[/tex].
We have been given that 12 times a number x is subtracted from 34, so our expression would be: [tex]34-12x[/tex].
12 times a number x is subtracted from 34, is greater than 0.8. We can represent this information in an inequality as:
[tex]34-12x>8[/tex]
Let us solve for x.
[tex]34-34-12x>8-34[/tex]
[tex]-12x>-26[/tex]
We know that dividing inequality by a negative number flips inequality sign.
[tex]\frac{-12x}{-12}<\frac{-26}{-12}[/tex]
[tex]x<\frac{13}{6}[/tex]
Therefore, the solution for our given inequality is [tex]x<\frac{13}{6}[/tex] and [tex](-\infty,\frac{13}{6})[/tex] interval notation.