Question

A pressure cooker contains 0.355 mole of air, which occupies a volume of 5.68 liters. The temperature inside the pressure cooker is 394 K. What is the absolute pressure of the air in the pressure cooker?

Answer 1

We will use ideal gas equation in this problem

PV = nRT

Where

P = pressure of gas or air = ?

V = volume of air = volume of pressure cooker = 5.68 L

T = temperature = 394 K

n = moles of air = 0.355

R = ideal gas equation = 0.0821 L atm / mol K

Putting values

Pressure = nRT / V = 0.355 X 0.0821 X 394 / 5.68 = 2.02 atm.

Answer 2

The answer is 205 kPa