Respuesta :
To solve this problem you must apply the proccedure shown below:
1. You have the following function:
[tex]y=-\frac{1}{2} (x-1)[/tex]
2. You can rewrite it as following:
[tex]y=\frac{(-x+1)}{2}[/tex]
3. The line intersects the y-axis when [tex]x=0[/tex], therefore:
[tex]y=\frac{(0+1)}{2}=\frac{1}{2} =0.5[/tex]
4. The line intersects the x-axis when [tex]y=0[/tex]:
[tex]0=\frac{(-x+1)}{2}\\ 0=-x+1\\ x=1[/tex]
5. Now plot the points (0, 0.5) and (1,0) in a graph , as you can see in the figure attached.
Therefore, the answer is: The points of intersection are (0, 0.5) and (1,0).
![Ver imagen carlosego](https://us-static.z-dn.net/files/d25/cb72f69a768ff5777e0fc747d6e6a089.jpg)
Answer:
Graph in attachment.
Step-by-step explanation:
Given: [tex]y=-\dfrac{1}{2}x-1[/tex]
To graph the line using intercepts with axis.
x-intercept and y-intercept
- For x-intercept, Put y=0 into equation
[tex]0=-\dfrac{1}{2}x-1[/tex]
[tex]x=-2[/tex]
x-intercept: (-2,0)
- For y-intercept, Put x=0 into equation
[tex]y=-\dfrac{1}{2}\cdot 0-1[/tex]
[tex]y=-1[/tex]
y-intercept: (0,-1)
Now draw the graph by plotting the points.
Please have a look with attachment for graph.
![Ver imagen isyllus](https://us-static.z-dn.net/files/d31/ad438bae70c581b7fd477c489dd4ffe2.jpg)