Question

The activation energy of a reaction is 56.9 kj/mol and the frequency factor is 1.5×1011/s. Part a calculate the rate constant of the reaction at 25 ∘c.

Answer 1

We will use Arrehenius equation

lnK = lnA  -( Ea / RT)

R = gas constant = 8.314 J / mol K

T = temperature = 25 C = 298 K

A = frequency factor

ln A = ln (1.5×10 ^11) = 25.73

Ea = activation energy = 56.9 kj/mol = 56900 J / mol

lnK = 25.73 - (56900 / 8.314 X 298) = 2.76

Taking antilog

K = 15.8

Answer 2

The rate constant of the reaction at 25 is mathematically given as

k=15.8

What is the rate constant of the reaction at 25?

Question Parameter(s):

The activation energy of a reaction is 56.9 kj/mol

The frequency factor is 1.5×1011/s.

Generally, the equation for the  Arrehenius equation   is mathematically given as

lnK = lnA  -( Ea / RT)

Theefore

ln A = ln (1.5×10 ^11)

ln A= 25.73

In conclusion

lnK = 25.73 - (56900 / 8.314 X 298)

lnk= 2.76

k=15.8

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