Answer : [tex]P(\text{ atleast one of the dice come up 3})= \frac{1}{5}[/tex]
Explanation :
We know that ,
Sample space of " sum of faces is 6"= [tex]\{(3,3),(4,2),(2,4),(5,1),(1,5)\}[/tex]
Atleast one of the dice come up 3 = [tex]\{(3,3)\}[/tex]
So,
[tex]Probability = \frac{\text{No. of favourable outcomes}}{\text{Total no. of outcomes}}[/tex]
[tex]P(\text{ atleast one of the dice come up 3})= \frac{1}{5}[/tex]