A survey asks participants if they support or oppose a 5% tuition increase at uf. If there are 580 respondents (selecting using a simple random sample) to a survey, what is the approximate margin of error?

Respuesta :

solution:

[tex]Approximate margin of error is given by=\frac{1}{\sqrt{n}}=\frac{1}{\sqrt{580}}\\

=0.041523\approx 0.0415\\

Approximate Margin of error=0.0415[/tex]