Consider the combustion of h2(g) 2h2(g)+o2(g)→2h2o(g). If hydrogen is burning at the rate of 0.49 mol/s, what is the rate of consumption of oxygen

Respuesta :

Answer : The rate of consumption of oxygen = 0.245 mol/s

Solution :  Given,

                 Rate at which Hydrogen burns = 0.49 mol/s

                 The Reaction is,

                       [tex]2H_{2}(g)+O_{2}(g)\rightarrow 2H_{2}O(l)[/tex]

    In this reaction,  2 moles of hydrogen react with the 1 mole of oxygen.

    The rate at which oxygen burns is equal to the half of rate at which hydrogen burns.

     Rate at which Oxygen burns = [tex]\frac{1}{2}[/tex] × 0.49 mol/s

                                                      = 0.245 mol/s

             


The study of chemicals and bonds s called chemistry. There are different types of chemical reactions and these are combination reaction, decomposition reaction and etc.

The correct answer is The rate of consumption of oxygen = 0.245 mol/s

What is a combination reaction?

When one or more elements of reactant join together to form a single compound is called a combination reaction.

Rate at which Hydrogen burns = 0.49 mol/s

The Reaction is,

  • [tex]2h_2(g)+o_2(g)---->2h_2o(g).[/tex]

                     

In this reaction,  2 moles of hydrogen react with 1 mole of oxygen.

The rate at which oxygen burns is equal to half of the rate at which hydrogen burns.

The ratee at which Oxygen burns = 1/2 × 0.49 mol/s

 = 0.245 mol/s

Hence, the correct answer is 0.245mol/s.

For more information about the reaction, refer to the link:-

https://brainly.in/question/9531558

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