Respuesta :

solution:

[tex]x^{2}+12x-7=0\\

add 7 to both side of the equation\\

x^{2}-12x=7\\

to creat a trinomial square on the left side of the equation.\\

find a value that is equal to the square of b and the cofficent of x.\\

(\frac{b}{2})^2=(-6)^2\\

add the term to each side of the equation\\

x^2-12x+(-6)^2=7+(-6)\\

x^2-12x+36=43\\

(x-6)^2=43\\

solve the equation for x.\\[/tex][tex]take the square root of each side of the equation to the set up the solution x,\\

(x-6)^2.\frac{1}{2}=\pm \sqrt{43}\\

x-6=\pm \sqrt{43}\\

x=6\pm \sqrt{43}[/tex]

Answer:

x^2+12x+36=7+36

Step-by-step explanation:

I just took the test.

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