Question

william and debra pierce are celebrating their 20th anniversary by having a reception hall. They have budgeted $4,500 for their reception. If the reception hall charge a $60 cleanup fee plus $30 per person, find the greatest number of people that they may invite and still stay within their budget.

Answer 1

Given- total budget of the party = $\ 4500$

reception hall charges for clean up =$\ 60$

extra fee per person =$\ 30$

Find out the number of people are invited.

To proof

let  us assume that the number of people are invited  in the reception are be x.

Given in the question the $\ 60$ be the clean up charge and  $\ 30$ be fee per person.

than equation become

⇒ 60 +30x = 4500

30x = 4500-60

30x = 4440

x = 148

The number of people are invited in the reception are 148

Hence proved

Answer 2

Answer:

William and Debra pierce can invite 140 people for the 20th anniversary.

Step-by-step explanation:

Total budget = 4500 $

Charge of cleanup = 60$

Remaining money = 4500 - 60 = 4440 $

Charge per person = 30 $

Number of persons they can invite

   $n=\frac{4440}{30}=\frac{444}{3}=148$

So William and Debra pierce can invite 140 people for the 20th anniversary.