(NEED ANSWER ASAP AND SHOW WORK)
4.) Use the diagram below to answer parts A-C. (4 Points Total) m∠HJL=(26x-7)° and m∠LJK=(10x+7)°

A.) What is the value of x?
B.) what is m∠HJL?
C.) What is m∠LJK

NEED ANSWER ASAP AND SHOW WORK 4 Use the diagram below to answer parts AC 4 Points Total mHJL26x7 and mLJK10x7 A What is the value of x B what is mHJL C What is class=

Respuesta :

Both angles are supplementary, which means that they both add up to 180°. To find the value of x, simply put the two equations together like this:

A.) [tex]26x - 7 + 10x + 7 = 180[/tex]

The -7 and +7 cancel each other out, which leaves us with

[tex]10x + 26x = 180[/tex]

--> [tex]36x = 180[/tex]

180 is 36 times bigger than x, so divide both sides by 36:

[tex]x = \frac{180}{36}[/tex]

x = 5

Now plug in the value of x:

B.) [tex]26(5) - 7 = 130 - 7 = [/tex] 123°

C.) [tex]10(5) + 7 = 50 + 7 =[/tex] 57°

To check your work, add them both up. [tex]123 + 57 = 180 degrees[/tex]

I hope you found this helpful. : )

Answer:

x=5

m∠HJL =123°

m∠LJK=57°

Step-by-step explanation:

m∠HJL=(26x-7)° and m∠LJK=(10x+7)°

∠HJL and ∠LJK are linear pair . the sum of angles = 180 degree

m∠HJL+ m∠LJK=180 degree

[tex](26x-7) +(10x+7)=180[/tex]

Combine like terms and solve for x

[tex]36x=180[/tex]

Divide by 36 on both sides

x=5

m∠HJL=(26x-7)=26(5)-7=123°

m∠LJK=(10x+7)=10(5)+7=57°

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