Solution: We are required to find the correlation between x and y here:
The formula for correlation is:
[tex]r=\frac{n\sum x y- \sum x \sum y}{\sqrt{[n\sum x^{2}-(\sum x)^2][n\sum y^{2}-(\sum y)^2]}}[/tex]
[tex]=\frac{6\times 159- 31 \times 18}{\sqrt{[6 \times 203-(31)^2][6 \times 258-(18)^2]}}[/tex]
[tex]=\frac{396}{560.8636}[/tex]
[tex]=0.7061[/tex]
[tex]\therefore r=0.7061[/tex]
Hence the option A. 0.7061 is correct
