We presume you want to find values of x that make this true.
Subtract the right side and factor:
[tex]2x^2-5x=0\\\\x(2x-5)=0\\\\\bf{x=0\qquad\text{or}\qquad x=\dfrac{5}{2}}[/tex]
Once you have factors whose product is zero, you can find the values of x that make those factors zero. A product can only be zero if one or more contributing factors is zero.
To solve 2x-5=0, you can add 5 then divide by 2:
... 2x -5 = 0
... 2x = 5
... x = 5/2
