Question

what is the step by step process of this problem? 6+2[-8-3(2x+4)]+10x

Answer 1

So with more than one pair of parentheses, you must start from the inside and make your way outside.

So firstly, distribute -3 to (2x + 4):

$6+2[-8-6x-12]+10x$

Next, combine like terms:

$6+2[-6x-20]+10x$

Next, distribute 2 to [-6x - 20]:

$6-12x-40+10x$

Lastly, combine like terms and your final answer will be $-2x-34$