Respuesta :
The quadratic function given by:
[tex]f(x)=a(x-h)^2+k, \ \ \ a\neq 0[/tex]
is in vertex form. The graph of [tex]f[/tex] is a parabola whose axis is the vertical line [tex]x=h[/tex] and whose vertex is the point [tex](h, k)[/tex]. So:
To translate the graph of a function to the right, left, upward or downward we have:
[tex]For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)[/tex]
By knowing this things, we can solve our problem as follows:
FIRST.
- Translating 11 units to the left:
[tex]g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2[/tex]
- Then translating 5 units down:
[tex]g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5[/tex]
Since the new function is fatter, the factor we need to multiply the term [tex](x+11)^2[/tex] must be less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.
Therefore, the right answer is b. f(x) = 1/2(x + 11)^2 - 5
SECOND.
- Translating 8 units to the right:
[tex]g(x)=f(x-8) \\ \\ \therefore g(x)=(x-8)^2[/tex]
- Then translating 1 unit down:
[tex]g(x)=f(x)-c \\ \\ \therefore g(x)=(x-8)^2-1[/tex]
As explained in the previous case, there are two factors 1/3 and 3, so we choose the first one.
Therefore, the right answer is a. g(x) = 1/3(x - 8)^2 - 1