Question

a certain car travels 20 km east then turns south for 13 km finally the car turns east again for 6 km

Answer 1

a^2+b^2=c^2

20km^2+13km^2=c^2

400km^2+169km^2=c^2

23.853720...km

Answer 2

Answer:

Total distance

$L = 39 km$

total displacement

$d = 29.1 km$

Explanation:

Total distance moved by the car is total path length of the car

$L = L_1 + L_2 + L_3$

$L = 20 + 13 + 6$

$L = 39 km$

now similarly we will have

total displacement of the car towards East

$x = 20 + 6 = 26 km$

total displacement of the car towards South

$y = 13 km$

now net displacement of the car is given as

$d = \sqrt{13^2 + 26^2}$

$d = 29.1 km$