Respuesta :

let x = 3+h
[tex] \frac{1}{(3 + h) + 2} \\ = \frac{1}{h + 3 + 2} \\ = \frac{1}{h + 5} [/tex]
The answer is A.

Answer: A. [tex]\dfrac{1}{h+5}[/tex]

Step-by-step explanation:

The given function: [tex]f(x)=\dfrac{1}{x+2}[/tex]

To find the value of [tex]f(3+h)[/tex], we need to  replace 'x' by (3+h) , we get

[tex]f(3+h)=\dfrac{1}{3+h+2}\\\\\Rightarrow\ f(3+h)=\dfrac{1}{3+2+h} .........................\text{[By commutative property ]}\\\\\Rightarrow\ f(3+h)=\dfrac{1}{5+h}\\\\\Rightarrow\ f(3+h)=\dfrac{1}{h+5}[/tex]

Hence, the value of [tex]f(3+h)=\dfrac{1}{h+5}[/tex]