Question

in outer space a constant net force of magnitude 140 degrees north is exerted on a 32.5 kg probe initially at rest what acceleration does this Force produce and how far does the probe travel in 10.0 seconds

Answer 1

Given That

Force = 140 N

Mass = 32.5 kg

So here we can use Newton's II law to find its acceleration

$F = ma$

$140 = 32.5* a$

$a = 4.31 m/s^2$

Now the probe is initially at rest

so distance covered in 10 s is required which we can find by using kinematics

$d = v_i*t + \frac{1}{2}at^2$

$d = 0 + \frac{1}{2}*4.31 * 10^2$

$d = 215.5 m$

so it will cover 215.5 m distance