Solve 13 14 15 please.
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[tex]x^2=144\\\\x=\pm\sqrt{144}=\pm12\ because\ (\pm12)^2=144\\\\x^3\dfrac{25}{289}\\\\x=\pm\sqrt{\dfrac{25}{289}}=\pm\dfrac{5}{17}\ because\ \left(\pm\dfrac{5}{17}\right)^2=\dfrac{25}{289}\\\\x^3=216\\\\x=\sqrt[3]{216}=6\ because\ 6^3=216[/tex]