boys (b): b
girls (g): b + 100
total (T) = b + g
I am going to set up the proportion as "boys" to "total"
[tex]\frac{3}{10} = \frac{b}{(b) + (b + 100)}[/tex]
⇒ [tex]\frac{3}{10} = \frac{b}{2b + 100}[/tex]
⇒ 3(2b + 100) = 10(b)
⇒ 6b + 300 = 10b
⇒ 300 = 4b
⇒ 75 = b
girls (g): b + 100 = (75) + 100 = 175
Answer: boys = 75, girls = 175