Question

On a photograph of a triangular piece of​ land, the lengths of the three sides are 12 cm, 15​ cm, and 21 cm respectively. The shortest side of the actual piece of land is 100m long. Find the lengths of the other two sides.

Answer 1

100/12=8⅓
multiply the other numbers by 8⅓ to get
15*8⅓=125
21*8⅓=175

the lengths are 100,125,175

Answer 2

The lengths of the other two sides are 250 m and 350 m.

Given that

On a photograph of a triangular piece of​ land, the lengths of the three sides are 12 cm, 15​ cm, and 21 cm respectively.

The shortest side of the actual piece of land is 100m long.

We have to find

The lengths of the other two sides.

According to the question

The lengths of the three sides are 12 cm, 15​ cm, and 21 cm respectively.

The shortest side of the actual piece of land is 100m long.

The length of the shortest side is 12 cm and an actual piece of land is 100m long.

Then,

$\rm 12 \ cm = 100 \ m\\\\1\ cm = \dfrac{200}{12}\\\\1 \ cm = \dfrac{50}{3}$

Therefore,

The lengths of the other two sides are,

$\rm 15 \ cm = 15 \times \dfrac{50}{3} \ m = 5 \times 50 = 250 \ m\\\\21 \ cm = 21 \times \dfrac{50}{3} \ m = 7 \times 50 = 350 \ m$

Hence, The lengths of the other two sides are 250 m and 350 m.

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