Respuesta :
Since, the boiling point of jet fuel = 329 °F
We have to convert the boiling point of jet fuel in [tex]^\circ C[/tex].
The expression which is used to convert [tex]^\circ F[/tex] to [tex]^\circ C[/tex] is given by:
C = [tex]\frac{5}{9}(F-32)[/tex]
= [tex]\frac{5}{9}(329-32)[/tex]
= [tex]\frac{5}{9}(297)[/tex]
= 165[tex]^\circ C[/tex]
Therefore, the boiling point of jet fuel is 165 [tex]^\circ C[/tex].
Answer:
Since, the boiling point of jet fuel = 329 °F
We have to convert the boiling point of jet fuel in .
The expression which is used to convert to is given by:
C =
=
=
= 165
Step-by-step explanation: