The deck has 4 aces, 4 kings and 4 queens.
When you start the game, you have a probability of 4/52 = 1/13 to pick up an ace.
Since there is no replacement, after you pick the first ace you have a probability of 4/51 of picking up a king. In fact, there are still 4 kings in the deck, but only 51 cards left (we already picked up the first ace.
Finally, for the same reason, you have a 4/50=2/25 probability of picking up a queen as the third card.
So, the probability of making these three picks one after the other is the product of all these probabilities:
[tex] \dfrac{1}{13} \times \dfrac{4}{51} \times \dfrac{2}{25} = \dfrac{1\times 4 \times 2}{13\times 51 \times 25} = \dfrac{8}{16575} [/tex]
