Remember:
6.022×10²³ molecules = 1 mol (Avogadro's number)
NH₃ = ammonia
To get molar mass of NH₃, add the mass of nitrogen + 3 times the mass of hydrogen (because there are 3 hydrogens in NH₃).
14.01 + 3(1.01) = 17.04 grams NH₃ = molar mass
1) Set up your equation. You want to cancel out molecules, and get to grams through moles.
So multiply 3.4×10²⁴ molecules of ammonia × 1 mol of ammonia × 17.04 grams of ammonia and divide it by 6.022×10²³ molecules of ammonia and 1 mol of ammonia.
3.4×10²⁴ molecules of ammonia × 1 mol of ammonia × 17.04 grams of ammonia
6.022×10²³ molecules of ammonia 1 mol of ammonia
Your answer should come out to be: 96.20724 grams of ammonia
Round to 2 sig figs: 96 grams of ammonia
