Question

an irregularly shaped stone was lowered into a graduated cylinder holding a volume of water equal to 2 ml. The height of the water rose to 7 ml. If the mass of the stone was 25 g, what was its density

Answer 1

The density of the stone is 5 g/cm³.

Mass = 25 g

Volume = 7 mL – 2 mL = 5 mL = 5 cm³

Density = mass/volume = 25 g/5 cm³ = 5 g/cm³

Answer 2

The density of the stone whose mass is 25 g and its volume is 5 mL is 5 g/mL.

We have a graduated cylinder holding a volume of water equal to 2 mL. After a stone is added, the height of the water rose to 7 mL. The volume of the stone is equal to the difference in the levels of water.

$V = 7 mL - 2 mL = 5 mL$

The stone has a volume of 5 mL and a mass of 25 g. Its density, that is the ratio of the mass to the volume, is:

$\rho = \frac{25g}{5mL} = 5 g/mL$

The density of the stone whose mass is 25 g and its volume is 5 mL is 5 g/mL.

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