The theoretical yield is 0.0110 g H₂.
Moles of H₂O = 0.0987 g H₂O × (1 mol H₂O/18.02 g H₂O) = 0.005 477 mol H₂O
Moles of H₂ = 0.005 477 mol H₂O × (2 mol H₂/2 mol H₂O) = 0.005 477 mol H₂
Theoretical yield of H₂ = 0.005 477 mol H₂ × (2.016 g H₂/1 mol H₂)
= 0.0110 g H₂
Answer: Theoretical yield of [tex]H_2[/tex] is 0.01 grams.
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
[tex]\text{Number of moles of}H_2O=\frac{0.0987g}{18g/mol}=0.005moles[/tex]
[tex]2H_2O\rightarrow 2H_2+O_2[/tex]
According to stoichiometry:
2 moles of water produces = 2 moles of hydrogen
Thus 0.005 moles of water produces =[tex]\frac{2}{2}\times 0.005=0.005[/tex] moles of hydrogen
Mass of [tex]H_2[/tex] produced =[tex]moles\times {\text {molar mass}}}=0.005\times 2g/mol=0.01g[/tex]
Thus theoretical yield of [tex]H_2[/tex] is 0.01 grams.
