solve tan(x)(tanx+1) =0
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The value of the variable x will be x = ±nπ and x = (3π/4 ± 2nπ). Then the correct option is A.
The connection between the lengths and angles of a triangular shape is the subject of trigonometry.
The equation is given below.
tanx (tanx + 1) = 0
For tan x = 0, the value of x will be
tan x = tan (±nπ)
x = ±nπ
For tan x + 1 = 0, the value of x will be
tan x + 1 = 0
tan x = –1
tan x = tan(3π/4 ± 2nπ)
x = (3π/4 ± 2nπ)
Then the correct option is A.
More about the trigonometry link is given below.
https://brainly.com/question/22698523
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