Question

In physics class, Carrie learns that a force, G, is equal to the mass of an object, m, times its acceleration, a. She writes the equation as G = ma, then realizes that each of her homework problems asks her to solve for acceleration. She rewrites the formula as = a. Using this formula, what is the acceleration of an object with F = 7.92 newtons and m = 3.6 kilograms? Express your answer to the nearest tenth.

Answer 1

Your problem statement is missing the formula Carrie came up with. It should be The one she started with, divided by m.

... G/m = a

For the values given, the acceleration is

... (7.92 N)/(3.6 kg) = 2.2 m/s²

_____

The unit of newtons is abbreviated N.

1 N = 1 kg·m/s² so dividing by kilograms leaves units of m/s², which are the units of acceleration.

Very likely, your question is not concerned with the units, just the number: 2.2. It's a straight division problem, easily handled by hand, by calculator, or in your head (after you realize 7.92 = 7.2×1.1 = 2×3.6×1.1).

Answer 2

The acceleration of the considered object for given force is evaluated to be $2.2 \: \rm m/s^2$

How to obtain acceleration from force applied on an object?

If the object is of mass m kg and force applied on it is of F N in the direction of motion, then the acceleration of that object is evaluated as:

$a= \dfrac{F}{m} \:\: \rm m/s^2$

For this case, we have got:

• Force on the object in direction of its motion: $F = 7.92 \: \rm N$
• Mass of the considered object: $m = 3.6 \: \rm kg$

Thus, its acceleration is evaluated as:

$a= \dfrac{F}{m} \:\: \rm m/s^2\\\\a = \dfrac{7.92}{3.6} = 2.2 \: \rm m/s^2$

Thus, the acceleration of the considered object for given force is evaluated to be $2.2 \: \rm m/s^2$

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