Respuesta :
Use distance formula d=sqrt root (y2-y1)^2+(x2-x1)^2. So (-3, 4) and (1, 7). D= sqrt root ( 7-4)^2+(-3+1)^2. So now solve d= sqrt (3)^2+(-2)^2. Now d= sqrt 9+4. D= sqrt 13 or 3.60555
The distance between the points (-3, 4) and (1, 7) is 5 units.
What is the length of any line on the graph?
The distance or length of any line on the graph,
[tex]D = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]
where,
d = distance/length of the line between point 1 and 2,
(x₁ , y₁) = coordinate of point 1,
(x₂ , y₂) = coordinate of point 2,
Given to us
Point 1: (-3, 4)
Point 2: (1, 7)
We know the formula to find the distance between two points on the coordinate plane, therefore, we will substitute the coordinates of the two points in the formula.
Point 1: (-3, 4) = (x₁ , y₁)
Point 2: (1, 7) = (x₂ , y₂)
The distance between the two points,
[tex]D = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\\\D = \sqrt{(7-4)^2+(1-(-3))^2}\\\\D = \sqrt{(3)^2+(4)^2}\\\\D = \sqrt{25}\\\\D = 5[/tex]
hence, the distance between the points (-3, 4) and (1, 7) is 5 units.
Learn more about Distance between Points:
https://brainly.com/question/4058851
