Question

Argon (Ar): [Ne]3s23p6

core electrons:__
valence electrons:__

Answer 1

Answer : Core electrons = 10

Valence electrons = 8

Explanation :

Core electrons : They are the electrons in an atom that do not participate in bonding.

Valence electrons : They are electrons in an atom that participate in bonding.

Electronic configuration : It is defined as the representation of electrons around the nucleus of an atom.  

Number of electrons in an atom are determined by the electronic configuration.

The electronic configuration of argon (Ar) will be:

$1s^22s^22p^63s^23p^6$

The electronic configuration of neon (Ne) will be:

$1s^22s^22p^6$

So, the electronic configuration of argon (Ar) in noble gas notation will be:

$[Ne]3s^23p^6$

In the given electronic configuration of argon, the electrons present in 1st shell and 2nd shell are the core electrons and the electrons present in 3rd shell are the valence electrons. That means,

Number of core electrons = 2 + 2 + 6 = 10

Number of valence electrons = 2 + 6 = 8

Answer 2

1. The core electrons are 10

2. The valence electrons are 8

Core electrons are electrons located in  the inner shells of and atom.

Valence electrons are electrons located on the outermost shell of an atom

From the question given above, we obtained:

Ar (18) => [Ne] 3s²3p⁶

Recall

Ne (10) => 1s² 2s²2p⁶

Therefore,

Ar (18) => [1s² 2s²2p⁶] 3s²3p⁶

From the above illustration,

Inner shell (core shell) => 1s² 2s²2p⁶

Outermost shell (valence shell) => 3s²3p⁶

1. Determination of the core electrons

Inner shell (core shell) => 1s² 2s²2p⁶

Core electrons = 2 + 2 + 6

Core electrons = 10

2. Determination of the valence electrons

Outermost shell (valence shell) => 3s²3p⁶

Valence electron = 2 + 6

Valence electron = 8

Learn more: https://brainly.com/question/15054861