Question

Determine the mass percent (to the hundredths place) of h in sodium bicarbonate (nahco3).

Answer 1

NaHCO3 = 84.0066 g/mol

H = 1.00794 g/mol

(1.00794 g/mol) / (84.0066 g/mol)

= 0.011998

= 1.20% H

Answer 2

The mass percent of H in NaHCO₃ is 1.19%

We'll begin by calculating the molar mass of NaHCO₃. This can be obtained as follow:

Molar mass of NaHCO₃ = 23 + 1 + 12 + (16×3)

= 23 + 1 + 12 + 48

= 84 g/mol

From the molar mass of NaHCO₃, we can see that 1 g of H is present in 84 g of the compound (NaHCO₃)

Finally, we shall determine the mass percent of H in NaHCO₃. This can be obtained as follow:

Mass of H = 1 g

Mass of NaHCO₃ = 84 g

Mass percent of H =?

Mass percent = $\frac{mass of element }{mass of compound } X 100$

Mass percent of H = $\frac{1}{84}$ × 100

Mass percent of H = 1.19%

Therefore, the mass percent of H in NaHCO₃ is 1.19%

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