Question

Calculate the magnitude of the electric field (in n/c) at 2.1 m from a point charge of 2.7 µc. You should round the answer to an integer, indicate only the number, do not include the unit.

Answer 1

solution:

$q=2.7\times 10^-6c r=2.1 E=\frac{kq}{r^2}  =\frac{9\times10^9\times2.7\times10^-6}{2.1^2} =\frac{9\times10^3\times2.7}{2.1^2} =9\times10^3\times4.28 =38.52\times10^3$