Question

(b) let's say a slingshot is used to shoot a marble straight up from the ground (s0 = 0) with an initial velocity of 11 meters per second. What is the marbles maximum height above the ground

Answer 1

Answer: 6.17 m

When a slingshot shoots a marble with initial velocity, $u=11 m/s$, it reaches a certain height $(s)$ and starts dropping from their under gravity $g=9.8m/s^2$. At the maximum height, instantaneous velocity, $v=0 m/s$

We would use the following equation of motion to find the maximum height reached:

$2as=v^2-u^2$

where, $a$is the acceleration , $s$ is the distance, $v$ is the final velocity, $u$ is the initial velocity.

$\Rightarrow s=\frac{v^2-u^2}{2a}=\frac{0-(11m/s)^2}{2\times-9.8m/s^2}=\frac{-121}{-19.6}m=6.17 m$

Marble reaches a maximum height of 6.17 m above the ground.