If hunter fires a bullet 2 degree below the horizontal
then the components of its speed is given as
[tex]v_x = v_o cos2[/tex]
[tex]v_y = v_o sin2[/tex]
so here initial speed of the bullet is not zero but have some magnitude in downwards direction
While the other bullet is dropped downwards so its initial speed will be zero
So here we can say
[tex]d = v_i*t + \frac{1}{2} at^2[/tex]
so if we use above equation we will find that the bullet that is shot at 2 degree below the horizontal will reach the ground first as its speed is more