Question

I need help with these two equations

Answer 1

Problem 1

$\dfrac{16}{(4- -3-1-8)}$

$\dfrac{16}{(4+3-1-8)}$

$\dfrac{16}{(7-9)} = \dfrac{16}{-2}$

-8  Answer

Problem 2

(8 - 3)^2 - (3 + 10)

5^2 - (13)

25 - 13

12 Answer

Answer 2

Problem 1

$\dfrac{16}{(4- -3-1-8)}$

$\dfrac{16}{(4+3-1-8)}$

$\dfrac{16}{(7-9)} = \dfrac{16}{-2}$

-8  Answer

Problem 2

(8 - 3)^2 - (3 + 10)

5^2 - (13)

25 - 13

12 Answer