Starting from 200 ft away, your friend skates toward you and then passes you. She skates at a constant speed of 20 ft/s. Her distance d from you in feet after t seconds is given by d=|200-20t|. At what times is she 60 ft from you?

Respuesta :

Your friend is 60 ft away from you at 7 seconds and 13 seconds.

Explanation

The distance of your friend [tex]d[/tex] from you in feet after [tex]t[/tex] seconds is given by.....

[tex]d= |200-20t|[/tex]

When the distance of your friend is 60 ft from you, then [tex]d= 60[/tex]. So....

[tex]60=|200-20t|[/tex]

While solving an absolute equation, we will take two cases - one for positive and another for negative. So....

[tex]60= 200-20t\\ \\ 60-200= -20t\\ \\ -140=-20t\\ \\ t= \frac{-140}{-20}=7[/tex]

and

[tex]-60=200-20t\\ \\ -60-200=-20t\\ \\ -260=-20t\\ \\ t=\frac{-260}{-20}=13[/tex]

Thus, your friend is 60 ft away from you at 7 seconds and 13 seconds.

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