Question

Some fertilizer blends contain magnesium nitrate (MgNO3). Suppose that a chemist has 1.24 liters of a 2.13 M solution of magnesium nitrate. If the chemist dilutes the solution to 1.60 M, what is the volume of the new solution?

Answer 1

The  volume of the new solution is

calculation

by use of the formula

M1V1= M2V2

M1 (molarity 1)  = 2.13 M

V1 (volume 1) = 1.24 l

M2 ( molarity 2) = 1.60 M

V2 (volume 2) = ?

by making V2 the subject of the formula

V2 = M1 V1/ M2

V2=( 1.24  x 2.13)÷ 1.60=  1.651 L