Answer:
The amount of heat needed is 62.79 Kj.
Explanation:
Given data:
Mass of water = 200 mL
Initial Temperature = 25 °C
Final temperature = 100 °C
Amount of heat required = ?
Solution:
specific heat of water is 4.186 j/g.°C
Mass of water
1 mL = 1g
200 mL = 200 g
Change in temperature
ΔT = T2 - T1
ΔT = 100 - 25 = 75 °C
Formula:
Q = m. c. ΔT
Q = amount of heat
m = mass
c = specific heat
ΔT = change in temperature
Now we will put the values in formula,
Q = m. c. ΔT
Q = 200 g. 4.186 j/g°C . 75 °C
Q = 62790 j
62790/1000
Q = 62.79 Kj
The amount of heat needed is 62.79 Kj.
